=LDR  00000nam  2200000   4500
=001  KASEL-06100000012033
=005  20100611142616.0
=008  181108|||||||||   |   |||   |||| ||ind||
=035  ##$$a 0010-061000000012033
=082   #$$a 532.076
=090  ##$$a 532.076/Ale/m
=100   #$$a ALEXANDROU, Andreas N.
=245    $$a Kunci penyelesaian soal - soal mekanika fluida edisi kedelapan jilid 1 dan 2
=250  ##$$a Ed. 8, Cet. 2
=260  ##$$a Jakarta $b Erlangga $c 1992
=300  ##$$a 194 hlm. ; 24 cm
=504  ##$$a 0
=650  # $$a UJIAN SOAL - MEKANIKA FLUIDA
=700   #$$a -
=985  ##$$a 1
=990  ##$$a 4848/Pro/10/93